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Solved: A water heater contains 55 gal of water. How many kilowatt-hours of energy are
Chapter 3, Problem 101P(choose chapter or problem)
A water heater contains 55 gal of water. How many kilowatt-hours of energy are necessary to heat the water in the water heater by \(25\ ^{\circ}\mathrm{C}\)?
Equation Transcription:
Text Transcription:
25 deg C
Questions & Answers
QUESTION:
A water heater contains 55 gal of water. How many kilowatt-hours of energy are necessary to heat the water in the water heater by \(25\ ^{\circ}\mathrm{C}\)?
Equation Transcription:
Text Transcription:
25 deg C
ANSWER:Solution 101P :
Step 1:
Amount of water = 55 gal.
= 25 °C
kilowatt-hours of energy necessary to heat the water in the water heater by 25 °C = ?
First, let’s convert gallon to Litres :
1 gallon of water = 3.7854 L
Therefore 55 gal in L is :
= 55 gal
= 208.19 L208 L
Specific heat of water = 4.186 J/g °C
Here we have to determine the amount of heat required to heat water. This can be calculated by the formula :
Q = mc