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Solved: A water heater contains 55 gal of water. How many kilowatt-hours of energy are

Chapter 3, Problem 101P

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QUESTION:

A water heater contains 55 gal of water. How many kilowatt-hours of energy are necessary to heat the water in the water heater by \(25\ ^{\circ}\mathrm{C}\)?

Equation Transcription:

Text Transcription:

25 deg C

Questions & Answers

QUESTION:

A water heater contains 55 gal of water. How many kilowatt-hours of energy are necessary to heat the water in the water heater by \(25\ ^{\circ}\mathrm{C}\)?

Equation Transcription:

Text Transcription:

25 deg C

ANSWER:

Solution 101P :

Step 1:

Amount of water = 55 gal.

= 25 °C

kilowatt-hours of energy necessary to heat the water in the water heater by  25 °C = ?

First, let’s convert gallon to Litres :

1 gallon of water = 3.7854 L

Therefore 55 gal in L is :

        = 55 gal

        = 208.19 L208 L

Specific heat of water = 4.186 J/g °C

Here we have to determine the amount of heat required to heat water. This can be calculated by the formula :

                Q = mc

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