When ice melts, it absorbs 0.33 kJ per gram. How much ice is required to cool a 12.0-oz drink from 75 °F to 35 °F, if the heat capacity of the drink is 4.18 J/g °C? (Assume that the heat transfer is 100% efficient.)
In this question it has given that the heat capacity of the drink= 4.18 J/g °C
Heat absorbs (q) = 0.33 KJ per gram
T1 = 35oF
= T2 -T1 = (75-35)oF = 40oF
It is known that,
1.0 oz = 28.3g.
Hence 12.0 oz will...