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Solved: A portable electric water heater transfers 255 watts (W) of power to 5.5 L of
Chapter 3, Problem 110P(choose chapter or problem)
A portable electric water heater transfers 255 watts (W) of power to 5.5 L of water, where 1 W = 1 J/s. How much time (in minutes) does it take for the water heater to heat the 5.5 L of water from \(25\ ^{\circ}\mathrm{C}\) to \(42\ ^{\circ}\mathrm{C}\)? (Assume that the water has a density of 1.0 g/mL.)
Questions & Answers
QUESTION:
A portable electric water heater transfers 255 watts (W) of power to 5.5 L of water, where 1 W = 1 J/s. How much time (in minutes) does it take for the water heater to heat the 5.5 L of water from \(25\ ^{\circ}\mathrm{C}\) to \(42\ ^{\circ}\mathrm{C}\)? (Assume that the water has a density of 1.0 g/mL.)
ANSWER:Solution 110P
Here, we are going to calculate the time taken by the water heater to heat the 5.5 L of water from 25oC to 42oC.
Step 1:
Given, density of water = 1.0 g/mL
Volume of water = 5.5 L = 5.5 x 1000 mL = 5500 mL [1 L = 1000 mL]
Using the relation density = mass/volume, we get,
Mass of water = density x volume
= 1.0 g/mL x 5500 mL
= 5500 g