Solution Found!
Shown is the cross section of a molded flat-belt pulley.
Chapter 9, Problem 9.128(choose chapter or problem)
Shown is the cross section of a molded flat-belt pulley. Determine its mass moment of inertia and its radius of gyration with respect to the axis \(A A^{\prime}\). (The density of brass is \(8650\mathrm{\ kg}/\mathrm{m}^3\) and the density of the fiber-reinforced polycarbonate used is \(1250\mathrm{\ kg}/\mathrm{m}^3\).)
Questions & Answers
QUESTION:
Shown is the cross section of a molded flat-belt pulley. Determine its mass moment of inertia and its radius of gyration with respect to the axis \(A A^{\prime}\). (The density of brass is \(8650\mathrm{\ kg}/\mathrm{m}^3\) and the density of the fiber-reinforced polycarbonate used is \(1250\mathrm{\ kg}/\mathrm{m}^3\).)
ANSWER:
Step by step solution Step 1 of 6Given thatDensity of brass isDensity of fiber inforced polycarbonate is