Write a formula for each ionic compound.
(a) copper(I) chlorate
(b) potassium permanganate
(c) lead(II) chromate
(d) calcium fluoride
(e) iron(II) phosphate
(f) lithium hydrogen sulfite
Solution 70P
Here, we are going to write a formula for each ionic compound.
- copper(I) chlorate
It is an anionic complex. So the name of the metal atom ends with “ate”. The oxidation state of Cu is 1+ which is written as Roman paranthas.
The formula of the ionic compound is CuClO3
(b) potassium permanganate
Here, K+ is potassium
[MnO4]- is a complex anion
Therefore, the formula of potassium permanganate is KMnO4
(c) lead(II) chromate
It is anionic complex ion. So the name of the metal atom ends with “ate”. The oxidation state of Pb is 2+ which is written as Roman paranthas.
Here, Pb2+ is Lead.
[CrO4]2- is a complex anion
Therefore, the formula of lead(II) chromate is PbCrO4
(d) calcium fluoride
Here, Ca2+ is calcium
F- is fluoride.
The formula of calcium fluoride is CaF2
(e) iron(II) phosphate
It is an cationic complex having PO43-
Therefore, the formula of iron(II) phosphate is Fe3(PO4)2
(f) lithium hydrogen sulfite
Here, Li+ is lithium
HSO3- is hydrogen sulfite
The formula of lithium hydrogen sulfite is LiHSO3