Solution Found!
Perform each calculation to the correct number of significant figures.(a) 4.5 × 0.03060
Chapter 2, Problem 57P(choose chapter or problem)
Perform each calculation to the correct number of significant figures.
(a) \(4.5 \times 0.03060 \times 0.391\)
(b) \(5.55 \div 8.97\)
(c) \(\left(7.890 \times 10^{12}\right) \div\left(6.7 \times 10^{4}\right)\)
(d) \(67.8 \times 9.8 \div 100.04\)
Equation Transcription:
Text Transcription:
4.5 x 0.03060 x 0.391
5.55 / 8.97
(7.890 x 10^12)(6.7 x 10^4)
67.8 x 9.8 / 100.04
Questions & Answers
QUESTION:
Perform each calculation to the correct number of significant figures.
(a) \(4.5 \times 0.03060 \times 0.391\)
(b) \(5.55 \div 8.97\)
(c) \(\left(7.890 \times 10^{12}\right) \div\left(6.7 \times 10^{4}\right)\)
(d) \(67.8 \times 9.8 \div 100.04\)
Equation Transcription:
Text Transcription:
4.5 x 0.03060 x 0.391
5.55 / 8.97
(7.890 x 10^12)(6.7 x 10^4)
67.8 x 9.8 / 100.04
ANSWER:Solution 57P
Step 1:
First let’s see the rules for significant numbers :
- All non-zero digits are considered significant. For example, 81 has two significant figures- 8 and 1, while 123.45 has five significant figures -1, 2, 3, 4 and 5.
- Zeros appearing anywhere between two non-zero digits are significant.
Example: 101.1203 has seven significant figures: 1, 0, 1, 1, 2, 0 and 3.
- Leading zeros are not significant. For example, 0.00052 has two significant figures: 5 and 2.
- Trailing zeros in a number containing a decimal point are significant. For example : 12.2300 has six significant figures: 1, 2, 2, 3, 0 and 0. The number 0.000122300 still has only six significant figures (the zeros before the 1 are not significant). In addition, 120.00 has five significant figures since it has three trailing zeros.
Rules for Rounding Off :
1. If the first digit to be dropped is 4 or less, then it and all following digits are simply dropped from the number.
2. If the first digit to be dropped is 5 or greater, then the last retained digit of the number is increased by 1.