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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 61p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 61p

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# Perform each calculation to the correct number of significant figures.(a) 87.6 + 9.888 + ISBN: 9780321910295 34

## Solution for problem 61P Chapter 2

Introductory Chemistry | 5th Edition

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Problem 61P

Problem 61P

Perform each calculation to the correct number of significant figures.

(a) 87.6 + 9.888 + 2.3 + 10.77

(b) 43.7 − 2.341

(c) 89.6 + 98.33 − 4.674

(d) 6.99 − 5.772

Step-by-Step Solution:
Step 1 of 3

Solution 61P

Here we have to calculate the correct number of significant figures. There are certain rules to track the significant figures from the calculated values. These are:

1. For addition and subtraction, the result should contain same number of decimal places, as the measurement is carried out with the fewest decimal places.
2. For multiplication and division,  the result should contain same number of decimal places, as the measurement is carried out with the fewest significant figures.

(a) 87.6 + 9.888 + 2.3 + 10.77

Here, addition operation is carried out

= 110.558

= 110.6

Thus, (a) have four  significant figures. Because 2.3 has the fewest ( one) decimal place. Thus correct number of significant figures of (a) is 110.6

(b) 43.7 − 2.341

Here, subtraction operation is carried out

= 41.359

= 41.4

(rounding off to three significant figures as it contains 43.7 which have only one decimal places. As well as, the leftmost removed digit is 5, so the preceding number is increased by 1)

Therefore  , 3 significant figures are there in(b)

Thus correct number of significant figures of (b) is 41.4

(c) 89.6 + 98.33 − 4.674

= 187.93 - 4.674 = 183.256

= 183.3

(rounding off to four significant figures, because the operation contains lowest 89.6 which have the fewest (one)  decimal places.)

Therefore , 4 significant figures are there in(C)

Thus correct number of significant figures of (C) is 183.3

(d) 6.99 − 5.772

= 1.218

= 1.22

(rounding off to three significant figures , because the operation contains 6.99 which have the lowest two decimal places)

As well as, the leftmost removed digit is more than 5, so the preceding number is increased by 1)

Therefore , 3 significant figures are there in(d)

Thus correct number of significant figures of (d) is 1.22

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: calculation, correct, figures, perform, significant. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The full step-by-step solution to problem: 61P from chapter: 2 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Perform each calculation to the correct number of significant figures.(a) 87.6 + 9.888 + 2.3 + 10.77(b) 43.7 ? 2.341(c) 89.6 + 98.33 ? 4.674(d) 6.99 ? 5.772” is broken down into a number of easy to follow steps, and 28 words. Since the solution to 61P from 2 chapter was answered, more than 482 students have viewed the full step-by-step answer.

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