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Solved: An aluminum engine block has a volume of 4.77 L and a mass of 12.88 kg. What is
Chapter 2, Problem 98P(choose chapter or problem)
An aluminum engine block has a volume of 4.77 L and a mass of 12.88 kg. What is the density of the aluminum in grams per cubic centimeter?
Questions & Answers
QUESTION:
An aluminum engine block has a volume of 4.77 L and a mass of 12.88 kg. What is the density of the aluminum in grams per cubic centimeter?
ANSWER:Step 1 of 2
Given: Mass = 12,88 kg and Volume = 4.77L
Conversion of unit:
We know,
1 kg =1000 g
1000 mL = 1L
1 cm3 =1 mL
The conversion factors are :\(\frac{1000 \mathrm{g}}{1 \mathrm{kg}}, \frac{1000 \mathrm{mL}}{1 L}, \frac{1 \mathrm{cm} 3}{1 \mathrm{ml}}\)
Volume of Al will be \(=4.77 \mathrm{L} \times \frac{\frac{1000 \mathrm{mL}}{1 L}}{1 \mathrm{L}}=4.77 \times 10^{3} \mathrm{mL}\)
Mass of the Al will be \(=12.88 \mathrm{kg} \times \frac{1000 \mathrm{g}}{1 \mathrm{kg}}=12.88 \times 10^{3} \mathrm{g}\)
Conversion of volume mL to cm3.
Volume of Al will be:
\(\begin{array}{l} =4.77 \mathrm{L} \times \frac{1000 \mathrm{mL}}{1 \mathrm{L}} \\ =4.77 \times 10^{3} \mathrm{mL} \times \frac{1 \mathrm{cm} 3}{1 \mathrm{mL}} \\ =4.77 \times 10^{3} \mathrm{cm}^{3} \end{array}\)