## Solution for problem 102P Chapter 2

# Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3.(a) What is the mass

Introductory Chemistry | 5th Edition

Acetone (fingernail-polish remover) has a density of \(0.7857\mathrm{\ g}/\mathrm{cm}^3\).

(a) What is the mass in grams of 17.56 mL of acetone?

(b) What is the volume in milliliters of 7.22 g of acetone?

Equation Transcription:

Text Transcription:

0.7857 g/cm^3

**Accepted Solution**

Step 1 of 3

Here, we are going to find the mass of 17.56 mL of acetone. Also, we are going to calculate the volume in millilitres of 7.22 g of acetone.

Density of any substance may be defined as mass per unit volume. If ‘d’ be the density, ‘m’ be the mass and ‘v’ be the volume of any substance, then, numerically,

d = ------- (1)

**Step 2 of 3**

**Step 3 of 3**

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Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3.(a) What is the mass