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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 104p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 104p

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# One of the particles in an atom is the proton. A proton has a radius of approximately

ISBN: 9780321910295 34

## Solution for problem 104P Chapter 2

Introductory Chemistry | 5th Edition

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Problem 104P

One of the particles in an atom is the proton. A proton has a radius of approximately $$1.0 \times 10^{-13}$$ cm and a mass of $$1.7 \times 10^{-24} \mathrm{~g}$$. Determine the density of a proton.

(Volume of a sphere = $$\frac{4}{3} \pi r^{3} ; \pi=3.14$$)

Equation Transcription:

1.0 × 10-13

1.7 × 10-24 g

Text Transcription:

1.0 × 10^-13

1.7 × 10^-24 g

4/3 pi r^3;=3.14

Step-by-Step Solution:

Solution 104P

Step 1:

Density=

Given that the mass of the proton is 1.7 × 10−24 g

The proton has a radius of 1.0 × 10−13 cm

Volume of the particle=4/3r3=4/3(1.0× 10−13)3

Step 2 of 2

##### ISBN: 9780321910295

The answer to “?One of the particles in an atom is the proton. A proton has a radius of approximately $$1.0 \times 10^{-13}$$ cm and a mass of $$1.7 \times 10^{-24} \mathrm{~g}$$. Determine the density of a proton.(Volume of a sphere = $$\frac{4}{3} \pi r^{3} ; \pi=3.14$$)Equation Transcription:1.0 × 10-13 1.7 × 10-24 gText Transcription:1.0 × 10^-13 1.7 × 10^-24 g4/3 pi r^3;=3.14” is broken down into a number of easy to follow steps, and 60 words. Since the solution to 104P from 2 chapter was answered, more than 459 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: proton, mass, Density, determine, atom. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The full step-by-step solution to problem: 104P from chapter: 2 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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