Solution Found!
For each reaction, identify tine substance being oxidized and the substance being
Chapter 16, Problem 36P(choose chapter or problem)
Problem 36P
For each reaction, identify tine substance being oxidized and the substance being reduced.
(a) Mg(s) + Br2(g) → MgBr2(s)
(b) 2 Cr3+(aq) + 3 Mn(s) → 2 Cr(s) + 3 Mn2+ (aq)
(c) 2 H+ (aq) + Ni(s) → H2(g) + Ni2+ (aq)
Questions & Answers
QUESTION:
Problem 36P
For each reaction, identify tine substance being oxidized and the substance being reduced.
(a) Mg(s) + Br2(g) → MgBr2(s)
(b) 2 Cr3+(aq) + 3 Mn(s) → 2 Cr(s) + 3 Mn2+ (aq)
(c) 2 H+ (aq) + Ni(s) → H2(g) + Ni2+ (aq)
ANSWER:
Problem 36P
For each reaction, identify the substance being oxidized and the substance being reduced.
(a)
(b)
(c)
Step by step solution
Step 1 of 3
(a)
Oxidizing agent is a substance that is easily reduced or gains electrons. Those elements that can form anions will serve as good oxidizing agents.
Reducing agents is a substance that is easily oxidized and loses electrons. Those elements that form cations will serve as good reducing agents.
The given reaction is as follows.
“Mg” is oxidized by loose electrons . Hence,it is a reducing agent.
reduced by accepting electrons. Hence, it is an oxidizing agent.
Therefore, “Mg” is a reducing agent and is an oxidizing agent.
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