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For each reaction, identify tine substance being oxidized and the substance being

Chapter 16, Problem 36P

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QUESTION:

Problem 36P

For each reaction, identify tine substance being oxidized and the substance being reduced.

(a) Mg(s) + Br2(g) → MgBr2(s)

(b) 2 Cr3+(aq) + 3 Mn(s) → 2 Cr(s) + 3 Mn2+ (aq)

(c) 2 H+ (aq) + Ni(s) → H2(g) + Ni2+ (aq)

Questions & Answers

QUESTION:

Problem 36P

For each reaction, identify tine substance being oxidized and the substance being reduced.

(a) Mg(s) + Br2(g) → MgBr2(s)

(b) 2 Cr3+(aq) + 3 Mn(s) → 2 Cr(s) + 3 Mn2+ (aq)

(c) 2 H+ (aq) + Ni(s) → H2(g) + Ni2+ (aq)

ANSWER:

Problem 36P

For each reaction, identify the substance being oxidized and the substance being reduced.

(a)

(b)

(c)

                                                     Step by step solution

Step 1 of 3

(a)

Oxidizing agent is a substance that is easily reduced or gains electrons. Those elements that can form anions will serve as good oxidizing agents.

Reducing agents is a substance that is easily oxidized and loses electrons. Those elements that form cations will serve as good reducing agents.

The given reaction is as follows.

                                           

“Mg” is oxidized by loose electrons . Hence,it is a reducing agent.

 reduced by accepting electrons. Hence, it is an oxidizing agent.

Therefore, “Mg” is a reducing agent and  is an oxidizing agent.

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