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Solved: For each of the reactions in 36, identify the oxidizing agent and the reducing
Chapter 16, Problem 38P(choose chapter or problem)
For each of the reactions in Problem 36 , identify the oxidizing agent and the reducing agent.
Problem 36:
(a) \(\mathrm{Mg}(s)+\mathrm{Br}_2(g) \longrightarrow \mathrm{MgBr}_2(s)\)
(b) \(2 \mathrm{Cr}^{3+}(a q)+3 \mathrm{Mn}(s) \longrightarrow 2 \mathrm{Cr}(s)+3 \mathrm{Mn}^{2+}(a q)\)
(c) \(2 \mathrm{H}^{+}(a q)+\mathrm{Ni}(s) \longrightarrow \mathrm{H}_2(g)+\mathrm{Ni}^{2+}(a q)\)
Questions & Answers
QUESTION:
For each of the reactions in Problem 36 , identify the oxidizing agent and the reducing agent.
Problem 36:
(a) \(\mathrm{Mg}(s)+\mathrm{Br}_2(g) \longrightarrow \mathrm{MgBr}_2(s)\)
(b) \(2 \mathrm{Cr}^{3+}(a q)+3 \mathrm{Mn}(s) \longrightarrow 2 \mathrm{Cr}(s)+3 \mathrm{Mn}^{2+}(a q)\)
(c) \(2 \mathrm{H}^{+}(a q)+\mathrm{Ni}(s) \longrightarrow \mathrm{H}_2(g)+\mathrm{Ni}^{2+}(a q)\)
ANSWER:Step 1 of 4
(a)
Oxidizing agent is a substance that is easily reduced or gains electrons. Those elements that can form anions will serve as good oxidizing agents.
Reducing agents is a substance that is easily oxidized and loses electrons. Those elements that form cations will serve as good reducing agents.