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Each of the following proposed mechanisms for the

Chapter 5, Problem 3P

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QUESTION:

Each of the following proposed mechanisms for the free-radical chlorination of methane is

wrong. Explain how the experimental evidence disproves each mechanism.

\(\mathrm{Cl}_{2}+\mathrm{hv} \rightarrow \mathrm{C} I_{2}^{*} \text { (an "activated" form of } \mathrm{Cl}_{2} \text { ) }\)

        \(\mathrm{C} I_{2}^{*}+\mathrm{CH}_{4} \rightarrow \mathrm{HCl}+\mathrm{CH}_{3} \mathrm{Cl}\)

\(\mathrm{CH}_{4}+\mathrm{hV} \rightarrow \mathrm{CH}_{3}+\mathrm{H}\)

        \(\mathrm{CH}_{3}+\mathrm{Cl}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{Cl}+\mathrm{Cl}\)

        \(\mathrm{Cl}+\mathrm{H} \rightarrow \mathrm{HCl}\)

Equation Transcription:

Text Transcription:

Cl2+hvCI2*(an "activated" form of Cl2)

CI2*+CH4HCl+CH3Cl

CH4+hvCH3+H

CH3+Cl2CH3Cl+Cl

Cl+HHCl

Questions & Answers

QUESTION:

Each of the following proposed mechanisms for the free-radical chlorination of methane is

wrong. Explain how the experimental evidence disproves each mechanism.

\(\mathrm{Cl}_{2}+\mathrm{hv} \rightarrow \mathrm{C} I_{2}^{*} \text { (an "activated" form of } \mathrm{Cl}_{2} \text { ) }\)

        \(\mathrm{C} I_{2}^{*}+\mathrm{CH}_{4} \rightarrow \mathrm{HCl}+\mathrm{CH}_{3} \mathrm{Cl}\)

\(\mathrm{CH}_{4}+\mathrm{hV} \rightarrow \mathrm{CH}_{3}+\mathrm{H}\)

        \(\mathrm{CH}_{3}+\mathrm{Cl}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{Cl}+\mathrm{Cl}\)

        \(\mathrm{Cl}+\mathrm{H} \rightarrow \mathrm{HCl}\)

Equation Transcription:

Text Transcription:

Cl2+hvCI2*(an "activated" form of Cl2)

CI2*+CH4HCl+CH3Cl

CH4+hvCH3+H

CH3+Cl2CH3Cl+Cl

Cl+HHCl

ANSWER:

Solution 3P:

Here, we are going to describe about the experimental evidence for each mechanism.

Step 1: (a)

It requires only one photon of light to generate CH3Cl. Thus the quantum yield for the reaction is only 1.0.

Quantum yield =

But, in actual, the quantum yield is so high which is more than several hundred. Thus, the high quantum yield indicates about a chain reaction.

Therefore, the above reaction is not a chain reaction. It has no propagation steps.

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