What would be the product ratio in the chlorination of propane if all the hydrogens were abstracted at equal rates?
Chlorination of propane can be carried out as follows:-
2CH3CH2CH2 + 2Cl2 CH3CH2CH2Cl + CH3CHClCH3 + 2HCl
This reaction involves two steps
(i) Initiation :- (This step involves the splitting of chlorine molecule)
Cl2 2 Cl.
(ii) Propagation:- ( This step involves the removal of primary and secondary hydrogen)
CH3 - CH2 - CH3 + Cl. CH3-CH2-CH2. Or CH3-C.H-CH3 + HCl
(primary radical) (secondary radical)
In the next step of propagation, the primary radical will undergo chlorination and form 1-chloropropane.
CH3-CH2-CH2. + Cl2 Cl-CH2-CH2-CH3 + Cl.
Or, CH3-C.H-CH3 + Cl2 CH3-CHCl-CH3 + Cl.