×
Get Full Access to Organic Chemistry - 8 Edition - Chapter 4 - Problem 18p
Get Full Access to Organic Chemistry - 8 Edition - Chapter 4 - Problem 18p

×

# What would be the product ratio in the chlorination of

ISBN: 9780321768414 33

## Solution for problem 18P Chapter 4

Organic Chemistry | 8th Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants

Organic Chemistry | 8th Edition

4 5 1 428 Reviews
29
4
Problem 18P

Problem 18P

What would be the product ratio in the chlorination of propane if all the hydrogens were abstracted at equal rates?

Step-by-Step Solution:

Solution:

Step 1

Chlorination of propane can be carried out as follows:-

2CH3CH2CH2 + 2Cl2   CH3CH2CH2Cl + CH3CHClCH3 + 2HCl

This reaction involves two steps

(i) Initiation :- (This step involves the splitting of chlorine molecule)

Cl2   2 Cl.

(ii) Propagation:- ( This step involves the removal of primary and secondary hydrogen)

CH3 - CH2 - CH3 +  Cl. CH3-CH2-CH2.   Or CH3-C.H-CH3  + HCl

In the next step of propagation, the primary radical  will undergo chlorination and form 1-chloropropane.

CH3-CH2-CH2.  + Cl2 Cl-CH2-CH2-CH3 + Cl.

(1-chloropropane)

Or, CH3-C.H-CH3  + Cl2 CH3-CHCl-CH3 + Cl.

(2-chloropropane)

Step 2 of 2

## Discover and learn what students are asking

Calculus: Early Transcendental Functions : Parametric Equations and Calculus
?In Exercises 1-4, find $$d y / d x$$. $$x=\sqrt[3]{t}, y=4-t$$

Calculus: Early Transcendental Functions : Second-Order Homogeneous Linear Equations
?Finding a General Solution In Exercises 5-30,find the general solution of the linear differential equation. y’’ - y' = 0

#### Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

What would be the product ratio in the chlorination of