2,3-Dimethylbutane reacts with bromine in the presence of light to give a monobrominated product. Further reaction gives a good yield of a dibrominated product. Predict the structures of these products, and propose a mechanism for the formation of the monobrominated product.
Step 1 </p>
Treatment of 2,3-dimethylbutane with bromine in the presence of light gives 2-bromo-2,3-dimethylbutane (monobromination product), which is further reacted with another mole of bromine in the presence of light gives 2,3-dibromo-2,3-dimethylbutane. Thus, the reaction is as follows: