When exactly 1 mole of methane is mixed with exactly 1 mole of chlorine and light is shone on the mixture, a chlorination reaction occurs. The products are found to contain substantial amounts of di-, tri-, and tetrachloromethane, as well as unreacted methane.
(a) Explain how a mixture is formed from this stoichiometric mixture of reactants, and propose mechanisms for the formation of these compounds from chloromethane.
(b) How would you run this reaction to get a good conversion of methane to CH3Cl? Of methane to CCl4?
Step 1 </p>
When one mole of methane is reacted with the chlorine it gives hydrochloric acid and methyl radical and the process goes on giving the di ,tri tetra methane molecules .
As CH3Cl is produced it can compete with CH4 for available Cl radical generating CH2Cl2.
This can generate CHCl3 .