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When ethene is treated in a calorimeter with H2 and a Pt

Chapter 5, Problem 52SP

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QUESTION:

When ethene is treated in a calorimeter with H2 and a Pt catalyst, the heat of reaction is found to be \(-137 \mathrm{~kJ} / \mathrm{mol}(+32.7 \mathrm{kcal} / \mathrm{mol})\), and the reaction goes to completion. When the reaction takes place at \(1400^{\circ} \mathrm{K}\), the equilibrium is found to be evenly balanced, with \(\mathrm{K}_{e q}=1\) Compute the value \(\Delta \mathrm{S}\) for this reaction.

Equation Transcription:

Text Transcription:

-137 kJ/mol (+32.7 kcal/mol)

1400°K

Keq=1

\Delta S

CH2=CH2+H2Pt catalyst CH3-CH3 H=-137 kJ/mol (-32.7kcal/mol)

Questions & Answers

QUESTION:

When ethene is treated in a calorimeter with H2 and a Pt catalyst, the heat of reaction is found to be \(-137 \mathrm{~kJ} / \mathrm{mol}(+32.7 \mathrm{kcal} / \mathrm{mol})\), and the reaction goes to completion. When the reaction takes place at \(1400^{\circ} \mathrm{K}\), the equilibrium is found to be evenly balanced, with \(\mathrm{K}_{e q}=1\) Compute the value \(\Delta \mathrm{S}\) for this reaction.

Equation Transcription:

Text Transcription:

-137 kJ/mol (+32.7 kcal/mol)

1400°K

Keq=1

\Delta S

CH2=CH2+H2Pt catalyst CH3-CH3 H=-137 kJ/mol (-32.7kcal/mol)

ANSWER:

Solution 26SP

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