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When ethene is treated in a calorimeter with H2 and a Pt
Chapter 5, Problem 52SP(choose chapter or problem)
When ethene is treated in a calorimeter with H2 and a Pt catalyst, the heat of reaction is found to be \(-137 \mathrm{~kJ} / \mathrm{mol}(+32.7 \mathrm{kcal} / \mathrm{mol})\), and the reaction goes to completion. When the reaction takes place at \(1400^{\circ} \mathrm{K}\), the equilibrium is found to be evenly balanced, with \(\mathrm{K}_{e q}=1\) Compute the value \(\Delta \mathrm{S}\) for this reaction.
Equation Transcription:
Text Transcription:
-137 kJ/mol (+32.7 kcal/mol)
1400°K
Keq=1
\Delta S
CH2=CH2+H2Pt catalyst CH3-CH3 H=-137 kJ/mol (-32.7kcal/mol)
Questions & Answers
QUESTION:
When ethene is treated in a calorimeter with H2 and a Pt catalyst, the heat of reaction is found to be \(-137 \mathrm{~kJ} / \mathrm{mol}(+32.7 \mathrm{kcal} / \mathrm{mol})\), and the reaction goes to completion. When the reaction takes place at \(1400^{\circ} \mathrm{K}\), the equilibrium is found to be evenly balanced, with \(\mathrm{K}_{e q}=1\) Compute the value \(\Delta \mathrm{S}\) for this reaction.
Equation Transcription:
Text Transcription:
-137 kJ/mol (+32.7 kcal/mol)
1400°K
Keq=1
\Delta S
CH2=CH2+H2Pt catalyst CH3-CH3 H=-137 kJ/mol (-32.7kcal/mol)
ANSWER:
Solution 26SP
Step 1