A solution of \(2.0 \mathrm{~g} \text { of }(+)-\text { glyceraldehyde, } \mathrm{HOCH}_{2}-\mathrm{CHOH}\), in \(10.0 \mathrm{~mL}\) of water was placed in a \(100-\mathrm{mm}\) cell. Using the sodium D line, a rotation of \(+1.74^{\circ}\) was found at

\(25^{\circ} \mathrm{C}\). Determine the specific rotation of \((+)-\text { glyceraldehyde }\)

Equation Transcription:

Text Transcription:

2.0 g of (+)-glyceraldehyde, HOCH2-CHOH

10.0 mL

100-mm

+1.74°

25°C

(+)-glyceraldehyde

Answer :

Step 1

Given that

Glyceraldehyde

Weight = 2 g.

Volume of water = 10.0 mL

Width of cell =100 mm.

Specific rotation =+1.74 o.

Temperature = 25 C.