Solution Found!
Show how you might use SN2 reactions to convert
Chapter 8, Problem 15P(choose chapter or problem)
Show how you might use \(S_{N} 2 \) reactions to convert \(1 \text { - chlorobutane }\) into the following compounds.
(a) \(\text { butan }-1-\text { ol }\)
(b) \(1 \text {-fluorobutane }\)
(c) \(1-\text { iodobutane }\)
(d) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{CN}\)
(e) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{C} \equiv \mathrm{CH}\)
(f) \(\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{O}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{CH}_{3}\)
(g) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{NH}_{2}\)
Equation Transcription:
Text Transcription:
S_N2
1-chlorobutane
butan-1-ol
1-flourobutane
1-iodobutane
CH_3-(CH_2)_3-CN
CH_3-(CH_2)_3-CCH
CH_3CH_2-O-(CH_2)_3-CH_3
CH_3-(CH_2)_3-NH_2
Questions & Answers
QUESTION:
Show how you might use \(S_{N} 2 \) reactions to convert \(1 \text { - chlorobutane }\) into the following compounds.
(a) \(\text { butan }-1-\text { ol }\)
(b) \(1 \text {-fluorobutane }\)
(c) \(1-\text { iodobutane }\)
(d) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{CN}\)
(e) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{C} \equiv \mathrm{CH}\)
(f) \(\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{O}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{CH}_{3}\)
(g) \(\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{NH}_{2}\)
Equation Transcription:
Text Transcription:
S_N2
1-chlorobutane
butan-1-ol
1-flourobutane
1-iodobutane
CH_3-(CH_2)_3-CN
CH_3-(CH_2)_3-CCH
CH_3CH_2-O-(CH_2)_3-CH_3
CH_3-(CH_2)_3-NH_2
ANSWER:
Solution 15P:
Here, we are going to write the complete reaction by SN2 mechanism for the product formation using 1-chlorobutane.
Step 1:
Second-Order Nucleophilic Substitution (SN2 Reaction) is a single step reaction, where , A strong nucleophile attacks the electrophilic carbon, forcing the leaving group to leave.
