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Textbooks / Chemistry / Introductory Chemistry 5 / Chapter 4 / Problem 120P

The atomic mass of germanium is 72.61 amu. Is it likely that any individual germanium

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 120P Chapter 4

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 120P

The atomic mass of germanium is 72.61 amu. Is it likely that any individual germanium atoms have a mass of 72.61 amu?

Step-by-Step Solution:
Step 1 of 3

Solution 120P

Ge have five naturally occurring isotopes from 70Ge, 72Ge, 73Ge, 74Ge, and 76Ge.  The atomic mass of germanium will the average atomic mass which is between the masses of the five isotopes.

70Ge = 20.52

72Ge =  27.45%

 73Ge = 7.76%

74Ge = 36.52%

76Ge= 7.75%

Therefore the standard atomic mass of germanium is calculated by using the standard formula

        = 0.2052 x 69.92 + 71.9 x 0.2745 + 72.9 x 0.0776+ 73.9x 0.3652+ 0.0775 x 75.9

                = 14.34 + 19.74 + 5.65+ 26.988+ 5.88

                = 72.63 amu.

Therefore, individual germanium atom has average atomic mass is 76.63 amu.

Step 2 of 3

Chapter 4, Problem 120P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The full step-by-step solution to problem: 120P from chapter: 4 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: AMU, mass, germanium, atoms, atomic. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The answer to “?The atomic mass of germanium is 72.61 amu. Is it likely that any individual germanium atoms have a mass of 72.61 amu?” is broken down into a number of easy to follow steps, and 22 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 120P from 4 chapter was answered, more than 1864 students have viewed the full step-by-step answer.

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