Carbon has two naturally occurring isotopes: carbon-12 (mass = 12.00 amu) and carbon-13 (mass = 13.00 amu). Chlorine also has two naturally occurring isotopes: chlorine-35 (mass = 34.97 amu) and chlorine-37 (mass = 36.97 amu). How many CCl4 molecules of different masses can exist? Determine the mass (in amu) of each of them.
Based on C-12, C-13 , Cl-35 and Cl-37, 10 different types of CCl4 is possible having different masses.
Here we have to calculate the formula mass of each compound.
Different types of compound are given in the table.
Formula mass in amu
Formula mass can be calculated as follows.
Formula mass = (no of atoms of the element ) x (atomic mass of 1st element) + (no of atoms of the element ) x (atomic mass of 2nd element) +...C12Cl335Cl37
Formula mass = 1 x (atomic mass of C-12) + 3 x (atomic mass of Cl-35) + 1 x (atomic mass of Cl-37)
= 1 x 12 amu + 1 x 36.97 amu + 3 x 34.97 amu
= 12 amu +104.91 amu + 36.97 amu
= 153.88 amu
The mass of the compound (1) C12Cl335Cl37 is 157.88 amu.
Formula mass = 1 x (atomic mass of C-12) + 2 x (atomic mass of Cl-37) +2 x (atomic mass of Cl-37)