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# Carbon has two naturally occurring isotopes: carbon-12 ISBN: 9780321910295 34

## Solution for problem 103P Chapter 5

Introductory Chemistry | 5th Edition

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Problem 103P

Carbon has two naturally occurring isotopes: carbon-12 (mass = 12.00 amu) and carbon-13 (mass = 13.00 amu). Chlorine also has two naturally occurring isotopes: chlorine-35 (mass = 34.97 amu) and chlorine-37 (mass = 36.97 amu). How many CCl4 molecules of different masses can exist? Determine the mass (in amu) of each of them.

Step-by-Step Solution:
Step 1 of 3

Solution 103P

Based on C-12, C-13 , Cl-35 and Cl-37, 10 different types of CCl4 is possible having different masses.

Here we have to calculate the formula mass of each compound.

Different types of compound are given in the table.

 Compound Formula mass in amu C12Cl335Cl37 153.88 amu C12Cl235Cl237 155.88 amu C12Cl35Cl337 157.88 amu C12Cl437 159.88 amu C12Cl435 151.88 amu C13Cl437 160.88 amu C13Cl435 152.88 amu C13Cl335Cl37 154.88 amu C13Cl235Cl237 156.88 amu C13Cl35Cl337 158.88 amu

Formula mass can be calculated as follows.

Formula mass = (no of atoms of the element ) x (atomic mass of 1st element) + (no of atoms of the element ) x (atomic mass of 2nd  element) +...

C12Cl335Cl37

Formula mass = 1 x (atomic mass of C-12) + 3 x (atomic mass of Cl-35) + 1 x (atomic mass of Cl-37)

=  1 x 12 amu + 1 x 36.97 amu + 3 x 34.97 amu

= 12 amu +104.91 amu + 36.97 amu

= 153.88 amu

The mass of the compound (1) C12Cl335Cl37 is 157.88 amu.

(2) C12Cl235Cl237

Formula mass = 1 x (atomic mass of C-12) + 2 x (atomic mass of Cl-37) +2 x (atomic mass of Cl-37)

=...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 103P from chapter: 5 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Carbon has two naturally occurring isotopes: carbon-12 (mass = 12.00 amu) and carbon-13 (mass = 13.00 amu). Chlorine also has two naturally occurring isotopes: chlorine-35 (mass = 34.97 amu) and chlorine-37 (mass = 36.97 amu). How many CCl4 molecules of different masses can exist? Determine the mass (in amu) of each of them.” is broken down into a number of easy to follow steps, and 53 words. Since the solution to 103P from 5 chapter was answered, more than 1344 students have viewed the full step-by-step answer. This full solution covers the following key subjects: AMU, mass, carbon, chlorine, naturally. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

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