Nitrogen has two naturally occurring isotopes: nitrogen-14 (mass= 14.00 amu) and nitrogen-15 (mass = 15.00 amu). Bromine also has two naturally occurring isotopes: bromine-79 (mass = 78.92 amu) and bromine-81 (mass = 80.92 amu). How many types of NBr3 molecules of different masses can exist? Determine the mass (in amu) of each of them.
Based on N-14, N-15 , Br-79 and Br-81, eight different types of NBr3 are possible having different masses.
Here we have to calculate the formula mass of each compound.
Different types of compound are given in the table.
Formula mass in amu
Formula mass can be calculated as follows.
Formula mass = (no of atoms of the element ) x (atomic mass of 1st element) + (no of atoms of the element ) x (atomic mass of 2nd element) +...N14Br279Br81
Formula mass = 1 x (atomic mass of N-14) + 2 x (atomic mass of Br-79) + 1 x (atomic mass of Br-81)
= 1 x 14 amu + 2 x 78.92 amu + 80.92 amu
= 252.76 amu
The mass of the compound (1) N14Br279Br81 is 252.76 amu
Formula mass = 1 x (atomic mass of N-14) + 1 x (atomic mass of Br-79) + 2 x (atomic mass of Br-81)
= 1 x 14 amu + 1 x 78.92 amu + 2x 80.92 amu
= 14 amu + 78.92 + 161.84 amu
= 254.76 amu
The mass of the compound (2) N14Br79Br281 is 254.76 amu.
Formula mass = 1...