Solution Found!
Are these steps for finding the solutions of correct (1)
Chapter 7, Problem 35E(choose chapter or problem)
Are these steps for finding the solutions of \(\sqrt{x+3}=3-x\) correct? \((1) \sqrt{x+3}=3-x\) is given; (2) \(x+3=x^{2}-6 x+9\), obtained by squaring both sides of \((1) ;(3) 0=x^{2}-7 x+6\), obtained by subtracting \(x+3\) from both sides of \((2) ;(4) 0=(x-1)(x-6)\), obtained by factoring the right-hand side of \((3) ;(5) x=1\) or \(x=6\), which follows from (4) because \(a b=0\) implies that \(a=0\) or \(b=0\).
Equation Transcription:
x + 3 = x2 − 6x + 9
(1); (3) 0 = x2 − 7x + 6
Text Transcription:
Square root x+3=3-x
x + 3 = x^2 − 6x + 9
(1); (3) 0 = x^2 − 7x + 6
Questions & Answers
QUESTION:
Are these steps for finding the solutions of \(\sqrt{x+3}=3-x\) correct? \((1) \sqrt{x+3}=3-x\) is given; (2) \(x+3=x^{2}-6 x+9\), obtained by squaring both sides of \((1) ;(3) 0=x^{2}-7 x+6\), obtained by subtracting \(x+3\) from both sides of \((2) ;(4) 0=(x-1)(x-6)\), obtained by factoring the right-hand side of \((3) ;(5) x=1\) or \(x=6\), which follows from (4) because \(a b=0\) implies that \(a=0\) or \(b=0\).
Equation Transcription:
x + 3 = x2 − 6x + 9
(1); (3) 0 = x2 − 7x + 6
Text Transcription:
Square root x+3=3-x
x + 3 = x^2 − 6x + 9
(1); (3) 0 = x^2 − 7x + 6
ANSWER:
Solution :
Step 1:
In this problem we have to find some conditions from the given value