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How many moles of gold atoms do 3.45 × 1024 gold atoms constitute?

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 18P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 18P

How many moles of gold atoms do \(3.45 \times 10^{24}\) gold atoms constitute?

Equation Transcription:

Text Transcription:

3.45 times 10^24

Step-by-Step Solution:

Solution 18P

Here, we are going to calculate the number of moles of gold atoms constituted by 3.45 x 1024 gold atoms.

Step 1:

One mole of any species is that quantity in number having a mass equal to its atomic or molecular mass in grams.

The number of particles (atoms, molecules or ions) present in 1 mole of any substance is fixed, with a value of 6.022 × 1023. This is an experimentally obtained value. This number is called the Avogadro Constant or Avogadro Number.

Step 2 of 2

Chapter 6, Problem 18P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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How many moles of gold atoms do 3.45 × 1024 gold atoms constitute?