What is the mass in grams of each elemental sample?(a) 6.64 mol W(b) 0.581 mol Ba(c)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 30P Chapter 6

Introductory Chemistry | 5th Edition

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Problem 30P

What is the mass in grams of each elemental sample?

(a) 6.64 mol W

(b) 0.581 mol Ba

(d) 1.57 mol S

Step-by-Step Solution:

Step 1 of 3

Solution 30P

There are three steps to converting moles of a substance to grams:

Determine how many moles are given in the problem.
Calculate the molar mass of the substance.
Multiply step one by step two.

(a) 6.64 mol W = The molar mass of W is 183.84 g/mol.

Thus the mass in gram is = 6.64 mol x (183.84 g/mol) = 1220 g W

(b) 0.581 mol Ba = The molar mass of Ba is 137.32 g/mol

Thus the mass in gram is = 0.581mol x (137.32 g/mol) = 79.782 g W

(The number of mol of Xe(68.1) given in the question seems wrong, The problem has been solved as per given data)

Thus the mass in gram is = 68.1 mol x (131.29 g/mol) = 8,940.849 g W

(d) 1.57 mol S =The molar mass of S is 32.065 g/mol

Thus the mass in gram is = 1.57 mol x (32.065 g/mol) = 50.34 g W

Step 2 of 3

Chapter 6, Problem 30P is Solved

Step 3 of 3

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

This full solution covers the following key subjects: mol, mass, grams, elemental, sample. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 30P from 6 chapter was answered, more than 2786 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 30P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “What is the mass in grams of each elemental sample?(a) 6.64 mol W(b) 0.581 mol Ba(c) 68.1 mol Xe(d) 1.57 mol S” is broken down into a number of easy to follow steps, and 22 words.