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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 35p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 35p

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# How many aluminum atoms are in 3.78 g of aluminum?

ISBN: 9780321910295 34

## Solution for problem 35P Chapter 6

Introductory Chemistry | 5th Edition

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Problem 35P

Problem 35P

How many aluminum atoms are in 3.78 g of aluminum?

Step-by-Step Solution:
Step 1 of 3

Solution 35P

Here, we have to calculate the number of atoms in 3.78 g of Aluminium.

We know,

Molar mass of Al =26.98 g/mol

1.0 mol of Al = 6.02 x1023 atoms of Al

1.0 mol of Al atoms = 26.98 g

The conversion factors are , (6.02 x1023 atoms of Al /1.0 mol of Al)

Therefore,

3.78 g of Aluminium contains

= 3.78 g  x  x  (6.02 x1023 atoms of Al /1.0 mol of Al)

= (22.7631/26.98) x 1023 atoms of Al

= 0.8437 x 1023 atoms of Al

= 8.437 x 1022 atoms of Al

Therefore, 3.78 g of aluminum contains 8.437 x 1022 atoms of Al

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 35P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: Aluminum, atoms. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “How many aluminum atoms are in 3.78 g of aluminum?” is broken down into a number of easy to follow steps, and 10 words. Since the solution to 35P from 6 chapter was answered, more than 1844 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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