How many aluminum atoms are in 3.78 g of aluminum?
Step 1 of 3
Here, we have to calculate the number of atoms in 3.78 g of Aluminium.
Molar mass of Al =26.98 g/mol
1.0 mol of Al = 6.02 x1023 atoms of Al
1.0 mol of Al atoms = 26.98 g
The conversion factors are , (6.02 x1023 atoms of Al /1.0 mol of Al)
3.78 g of Aluminium contains
= 3.78 g x x (6.02 x1023 atoms of Al /1.0 mol of Al)
= (22.7631/26.98) x 1023 atoms of Al
= 0.8437 x 1023 atoms of Al
= 8.437 x 1022 atoms of Al
Therefore, 3.78 g of aluminum contains 8.437 x 1022 atoms of Al
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 35P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: Aluminum, atoms. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “How many aluminum atoms are in 3.78 g of aluminum?” is broken down into a number of easy to follow steps, and 10 words. Since the solution to 35P from 6 chapter was answered, more than 1844 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.