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What is the mass of 4.91 × 1021 platinum atoms?

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 36P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 36P

What is the mass of 4.91 × 1021 platinum atoms?

Step-by-Step Solution:

Solution 36P

Here, we are going to calculate the mass of 4.91 x 1021 platinum atoms.

Step 1:

One mole of any species is that quantity in number having a mass equal to its atomic or molecular mass in grams.

The number of particles (atoms, molecules or ions) present in 1 mole of any substance is fixed, with a value of 6.022 × 1023. This is an experimentally obtained value. This number is called the Avogadro Constant or Avogadro Number.

Step 2:

The number of moles = given number of particles / Avogadro number

Therefore, number of moles of platinum = 4.91 x 1021 / 6.022 × 1023

                                             = 0.815 x 10-2

                                             = 8.15 x 10-3 mol.

Step 3 of 3

Chapter 6, Problem 36P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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