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Determine the mass of each sample.(a) 1.32 mol carbon

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 48P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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5
Problem 48P

Determine the mass of each sample.

(a) 1.32 mol carbon tetrafluoride

(b) 0.55 mol magnesium fluoride

(c) 1.29 mmol carbon disulfide

(d) 1.89 kmol sulfur trioxide

Step-by-Step Solution:
Step 1 of 3

Solution 48P

There are three steps to converting moles of a substance to grams:

Determine how many moles are given in the problem.Calculate the molar mass of the substance.Multiply step one by step two.

(a) 1.32 mol carbon tetrafluoride

  The molar mass of CF4 is 88.0043 g/mol. Thus the mass in gram = 1.32  88.0043 = 116.165g

(b)  0.55 mol magnesium fluoride

The molar mass of MgF2 is 62.3018 g/mol. Thus the mass in gram = 0.55 62.3018...

Step 2 of 3

Chapter 6, Problem 48P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “Determine the mass of each sample.(a) 1.32 mol carbon tetrafluoride(b) 0.55 mol magnesium fluoride(c) 1.29 mmol carbon disulfide(d) 1.89 kmol sulfur trioxide” is broken down into a number of easy to follow steps, and 22 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: carbon, mol, mass, fluoride, kmol. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 48P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 48P from 6 chapter was answered, more than 2148 students have viewed the full step-by-step answer.

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