Problem 60P
How many moles of O are in 12.4 mol Fe(NO3)3?
Step-by-Step Solution:
Step 1 of 3
Solution 60P
Fe(NO3)3----------->Fe3+ + 3 NO3-
I mole of Fe(NO3)3 contains 9 moles of oxygen atoms
Therefore 12.4 moles of Fe(NO3)3 will contain 12.49 moles of O=111.6 moles of oxygen atoms
Step 2 of 3
Chapter 6, Problem 60P is Solved
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Step 3 of 3
