Calculate the mass percent composition of nitrogen in each compound.

(a) N2O

(b) NO

(c) NO2

(d) N2O5

Solution 79P

1) Mass of one mole of N2O = molar mass of N2O

= (14 * 2) + 16

= 44 g

Number of N moles in one N2O mole = 2

Mass of one mole of N = molar mass of N =14g

Therefore, mass of N in one mole of N2O = 14 * 2 = 28 g

But one mole of N2O means 44g of N2O

Therefore percentage mass of N in N2O = (28 g / 44 g) * 100 %

= 63.63 % .

2) mass of one mole of NO=molar mass of NO

=14+16

=30.

Number of N moles of one NO mole =1

Mass of one mole of N=molar mass of N=14 g.

Therefore ,mass of N in one mole of NO=14*1=14g

But one mole of NO means 30 g of NO.

Therefore ,mass of N in NO=(14/30)*100

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