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Solved: Samples of several compounds are decomposed, and

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 90P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 90P

Samples of several compounds are decomposed, and the masses of their constituent elements are measured. Calculate the empirical formula for each compound.

(a) 2.677 g Ba, 3.115 g Br

(b) 1.651 g Ag, 0.1224 g O

(c) 0.672 g Co, 0.569 g As, 0.486 g O

Step-by-Step Solution:

Solution 90P

Here, we have to calculate the empirical formula of each compound.

(a) 2.677 g Ba, 3.115 g Br

Step 1 :

Given the masses of each element :

Ba = 2.677 g

Br = 3.115 g

Step 2:

Conversion of the masses to moles by using the molar mass for each element as a

conversion factor.

2.677 g of Ba x  = 0.01949 mol Ba

3.115 g Br x = 0.03898 mol Br

Step 3:

The pseudo empirical formula of the compound is

Ba0.0195 Br 0.03898

Step 4:

Divide by the lowest, having  the smallest whole-number ratio

Ba =  =1

Br =  =2

Step 5:

The correct empirical formula of the compound (a) is BaBr2

b) 1.651 g Ag, 0.1224 g O

Step 1 :

Given the masses of each element :

Ag = 1.651g

O= 0.1224 g

Step 2:

Conversion of the masses to moles by using the molar mass for each element as a

conversion factor.

1.651g of Ag x  = 0.0153mol Ag

0.1224 g O x = 0.00765 mol O

Step 3: 

The pseudo empirical formula of the compound is

Ag0.0153 O0.00765

Step 4:

Divide by the lowest, having  the smallest whole-number ratio

O =  =1

Ag =  =2

Step 5:

The correct empirical formula of the compound (b) is Ag2O.

(c) 0.672 g Co, 0.569 g As, 0.486 g O

Step 1 :

Given the masses of each element :

Co = 0.672 g

As= 0.569 g  

O = 0.486 g

Step 2:

Conversion of the masses to moles by using the molar mass for each element as a

conversion factor.

 0.672 g of Co x  = 0.02399 mol Co

0.569 g  of  As  x = 0.00759 mol As

0.486 g of  O  x = 0.030375 mol O

Step 3:

The pseudo empirical formula of the compound is

Co0.02399 As0.00759O0.030375

Step 4 of 5

Chapter 6, Problem 90P is Solved
Step 5 of 5

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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