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Solved: A 0.77-mg sample of nitrogen reacts with chlorine to form 6.61 mg of the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 97P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 97P

Problem 97P

A 0.77-mg sample of nitrogen reacts with chlorine to form 6.61 mg of the chloride. What is the empirical formula of the nitrogen chloride?

Step-by-Step Solution:
Step 1 of 3

Solution 97P

The empirical formula can be found using the table given below.The number of moles of each elements is obtained and the simplest whole number ratio in which the elements are present in the compound is  found.

 

Elements

Mass of the elements

Atomic weight

Number of moles

N

0.77

14

0.77/14=0.055

Cl

5.84

35

5.84/35=0.167

 The simplest ratio in which the elements Nitrogen and Chlorine is present is 1:3(0.167/0.055=3).So the empirical formula should be NCl3

 

Step 2 of 3

Chapter 6, Problem 97P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: A 0.77-mg sample of nitrogen reacts with chlorine to form 6.61 mg of the