Solution Found!
Solved: A 45.2-mg sample of phosphorus reacts with selenium to form 131.6 mg of the
Chapter 6, Problem 98P(choose chapter or problem)
QUESTION:
A 45.2-mg sample of phosphorus reacts with selenium to form 131.6 mg of the selenide. What is the empirical formula of the phosphorus selenide?
Questions & Answers
QUESTION:
A 45.2-mg sample of phosphorus reacts with selenium to form 131.6 mg of the selenide. What is the empirical formula of the phosphorus selenide?
ANSWER:Step 1 of 2
The empirical formula can be found using the table given below. The number of moles of each elements is obtained and the simplest whole number ratio in which the elements are present in the compound is found.