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Complete the table.26. Element27. Moles28. Number of Atoms29. Ne30. 0.55231.32. Ar33.34

Chapter 6, Problem 21P

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QUESTION:

Complete the table.

\(\begin{array}{lll} \hline \text { Element } & \text { Moles } & \text { Number of Atoms } \\ \hline \mathrm{Ne} & 0.552 & - \\ \mathrm{Ar} & - & 3.25 \times 10^{24} \\ \mathrm{Xe} & 1.78 & - \\ \mathrm{He} & - & 1.08 \times 10^{20} \\ \hline \end{array}\)

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QUESTION:

Complete the table.

\(\begin{array}{lll} \hline \text { Element } & \text { Moles } & \text { Number of Atoms } \\ \hline \mathrm{Ne} & 0.552 & - \\ \mathrm{Ar} & - & 3.25 \times 10^{24} \\ \mathrm{Xe} & 1.78 & - \\ \mathrm{He} & - & 1.08 \times 10^{20} \\ \hline \end{array}\)

ANSWER:

 

Step 1 of 2

(i) Number of atoms in 0.552 moles of \(\mathrm{Ne}=6.023 \times 10^{23} \times 0.552 \text { atoms }=3.32 \times 10^{23} \text { atoms }\)

(ii) \(\text { Number of moles in Argon }=\frac{\text { Number of atoms }}{6.023 \times 10^{23}}=\frac{3.25 \times 10^{24}}{6.023 \times 10^{23}}=5.39 \text { moles }\)

(iii) Number of atoms in 1.78 moles of \(\mathrm{Ne}=6.023 \times 10^{23} \times 1.78 \text { atoms }=1.07 \times 10^{24} \text { atoms }\)

(iv) \(\text { Number of moles in Argon }=\frac{\text { Number of atoms }}{6.023 \times 10^{23}}=\frac{1.08 \times 10^{20}}{6.023 \times 10^{23}}=1.7 \times 10^{-4} \mathrm{moles}\)

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