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Solved: Complete the table.SubstanceMassMolesNumber of

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 108P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 108P

Complete the table.

Substance

Mass

Moles

Number of Particles (atoms or molecules)

C6H12O6

15.8 g

______

______

Pb

______

______

9.04 × 1021

CF4

22.5 mg

______

______

C

______

0.0388

______

Step-by-Step Solution:
Step 1 of 3

Solution  108P

The complete table is given below.

Substance

Mass

Moles

Number of Particles (atoms or molecules)

C6H12O6

15.8 g

0.0877 moles

0.528 x 1023 molecules

Pb

3.110 g

0.0150  moles

9.04 × 1021

CF4

22.5 mg

0.000256  moles

1.54 x 1020 molecules.

C

0.4659 g 

0.0388

0.2337 x 1023 atoms

The molar mass of C6H12O6 = 6 x 12.01 g/mol + 12 x 1.008 g/mol + 6 x16 g/mol

                        = 180.156 g/mol

Thus,

180.156 g = 1 mol

1 mol = 6.023 x 1023 molecules

15.8 g contains = 15.8 g x = 0.0877 mol

15.8 g contains = 15.8 g  x x  = 0.528 x 1023 molecules

(2) The molar mass of Pb  = 207.2  g/mol

207.2 g = 1 mol

1 mol = 6.023 x 1023 atoms  = 207.2 g

1000 mg =1 g

9.04 x 1021 contains = 9.04 x 1021  x = 0.0150  mol

9.04 x 1021 contains  =  9.04 x 1021  atoms x    x...

Step 2 of 3

Chapter 6, Problem 108P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: Complete the table.SubstanceMassMolesNumber of

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