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# Solved: Complete the table.SubstanceMassMolesNumber of ISBN: 9780321910295 34

## Solution for problem 108P Chapter 6

Introductory Chemistry | 5th Edition

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Problem 108P

Complete the table.

 Substance Mass Moles Number of Particles (atoms or molecules) C6H12O6 15.8 g ______ ______ Pb ______ ______ 9.04 × 1021 CF4 22.5 mg ______ ______ C ______ 0.0388 ______
Step-by-Step Solution:
Step 1 of 3

Solution  108P

The complete table is given below.

 Substance Mass Moles Number of Particles (atoms or molecules) C6H12O6 15.8 g 0.0877 moles 0.528 x 1023 molecules Pb 3.110 g 0.0150  moles 9.04 × 1021 CF4 22.5 mg 0.000256  moles 1.54 x 1020 molecules. C 0.4659 g 0.0388 0.2337 x 1023 atoms
The molar mass of C6H12O6 = 6 x 12.01 g/mol + 12 x 1.008 g/mol + 6 x16 g/mol

= 180.156 g/mol

Thus,

180.156 g = 1 mol

1 mol = 6.023 x 1023 molecules

15.8 g contains = 15.8 g x = 0.0877 mol

15.8 g contains = 15.8 g  x x = 0.528 x 1023 molecules

(2) The molar mass of Pb  = 207.2  g/mol

207.2 g = 1 mol

1 mol = 6.023 x 1023 atoms  = 207.2 g

1000 mg =1 g

9.04 x 1021 contains = 9.04 x 1021  x = 0.0150  mol

9.04 x 1021 contains  =  9.04 x 1021  atoms x x...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

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