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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 109p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 109p

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# Solved: Determine the chemical formula of each compound and refer to the formula to ISBN: 9780321910295 34

## Solution for problem 109P Chapter 6

Introductory Chemistry | 5th Edition

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Problem 109P

Determine the chemical formula of each compound and refer to the formula to calculate the mass percent composition of each constituent element.

(a) copper(II) iodide

(b) sodium nitrate

(d) calcium fluoride

Step-by-Step Solution:
Step 1 of 3

Solution 109P

Here, we have to calculate the mass percent composition of each constituent element.The mass percent composition or mass percent of an element is that the  percentage  of the element present in  compound’s total mass.

% mass = (mass of element in 1 mole of the compound) / (molar mass of the compound) x 100%

(a) copper(II) iodide

The chemical formula of the compound is CuI2.

Molar mass of Copper iodide = 63.546 g/mol + 2x 126.904 g/mol

= 317.354 g/mol

Molar mass of Cu = 63.456 g/mol

Molar mass of I = 126.904 g/mol

Thus,

Mass percent of I = x 100

=  79.97% Mass percent of Cu = x 100

=  19.99 % Thus, the chemical formula of the compound is CuI2.

And  the mass percent of Cu is 19.99 % and

The mass percent of I is 79.97% (b) sodium nitrate

The chemical formula of the compound is NaNO3.

Molar mass of Na = 22.989 g/mol

Molar mass of N = 14.0 g/mol

Molar mass of O = 16.0 g/mol

Molar mass of NaNO3 = 22.989 g/mol + 14.0 g/mol +3 x 16.0 g/mol

= 84.989 g/mol

Thus,

Mass percent of Na = x 100

=  27.05  %

Mass percent of N  = x 100

=  16.47 %

Mass percent of O  = x 100

=  56.47 %

Thus, the chemical formula of the compound is NaNO3 and

the mass percent of Na is 27.05%

The mass percent of N is 16.47 %

The mass percent of O is 56.47 %

The chemical formula of the compound is PbSO4.

Molar mass of Pb  = 207.2  g/mol

Molar mass of S = 32.065 g/mol

Molar mass of O = 16.0 g/mol

Molar mass of PbSO4 = 207.2  g/mol + 32.065 g/mol + 4 x 16.0 g/mol

= 303.265 g/mol

Thus,

Mass percent of Pb = x 100

=  68.32  %

Mass percent of S  = x 100

=  10.57 %

Mass percent of O  = x 100

=  21.10  %

Thus, the chemical formula of the compound is PbSO4 and

the mass percent of Pb  is 68.32  %

The mass percent of S is 10.57 %

The mass percent of O is 21.10  %

(d) calcium fluoride

The chemical formula of the compound is CaF2.

Molar mass of Ca  =40.078  g/mol

Molar mass of F = 18.998 g/mol

Molar mass of CaF2  = 40.078  g/mol + 2x 18.998 g/mol

= 78.074 g/mol

Thus,

Mass percent of Ca = x 100

=  51.333   %

Mass percent of  F   = x 100

=  48.666  %

Thus, the chemical formula of the compound is CaF2   and

the mass percent of Ca  is 51.33 %

The mass percent of F is 48.66 %

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 109P from chapter: 6 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: formula, fluoride, chemical, composition, compound. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 109P from 6 chapter was answered, more than 542 students have viewed the full step-by-step answer. The answer to “?Determine the chemical formula of each compound and refer to the formula to calculate the mass percent composition of each constituent element.(a) copper(II) iodide (b) sodium nitrate (c) lead(II) sulfate (d) calcium fluoride” is broken down into a number of easy to follow steps, and 33 words.

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