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The rock in a lead ore deposit contains 84% PbS by mass.

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 112P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 112P

The rock in a lead ore deposit contains 84% PbS by mass. How many kilograms of the rock must a mining company process to obtain 1.0 kg of Pb?

Step-by-Step Solution:

Solution 112P

Here, we are going to calculate the mass of rock required by the mining company to obtain 1.0 kg of Pb.

Step 1:

Molar mass of PbS = atomic mass of Pb + atomic mass of S

                        = 207.2 + 32.065                        

                        = 239.265 g/mol

Step 2:

Now, mass percentage of Pb in PbS = (207.2 / 239.265) x 100

                                        = 86.6 %

I.e., in one kg of PbS, (86.6/100 = 0.866) kg of Pb is present.

Step 3 of 4

Chapter 6, Problem 112P is Solved
Step 4 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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The rock in a lead ore deposit contains 84% PbS by mass.

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