Problem 127P

An iron ore contains 38% Fe203 by mass. What is the maximum mass of iron that can be recovered from 10.0 kg of this ore?

Solution 127P

Here, we are going to calculate the maximum mass of iron that can be recovered from 100 kg of the ore.

Step 1:

Given 38% of Fe2O3 by mass

Mass of Fe2O3 in 10kg = x 10 x 1000 g = 3800 g =3.8 kg

% of Fe in Fe2O3 = = 0.699