An iron ore contains 38% Fe203 by mass. What is the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 127P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 127P

An iron ore contains 38% Fe203 by mass. What is the maximum mass of iron that can be recovered from 10.0 kg of this ore?

Step-by-Step Solution:

Solution 127P

Here, we are going to calculate the maximum mass of iron that can be recovered from 100 kg of the ore.

Step 1:

Given 38% of Fe2O3 by mass

Mass of Fe2O3 in 10kg = x 10 x 1000 g = 3800 g =3.8 kg

% of Fe in Fe2O3 = = 0.699

Step 2 of 2

Chapter 6, Problem 127P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

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An iron ore contains 38% Fe203 by mass. What is the

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