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Solved: Pair each cation on the left with an anion on the right that will form a soluble

Chapter 7, Problem 62P

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QUESTION:

Pair each cation on the left with an anion on the right that will form a soluble compound with it and write a formula for the soluble compound. Use each anion only once.

\(\begin{array}{ll}\mathrm{Na}^+&\ \ \ \ \ \mathrm{\ NO}_3-\\
\mathrm{Sr}^{2+}&\mathrm{\ \ \ \ \ \ SO}_4^{2-}\\
\mathrm{Co}^{2+}&\mathrm{\ \ \ \ \ \ S}^{2-}\\
\mathrm{Pb}^{2+}&\mathrm{\ \ \ \ \ \ CO}_3^{2-}\end{array}\)

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QUESTION:

Pair each cation on the left with an anion on the right that will form a soluble compound with it and write a formula for the soluble compound. Use each anion only once.

\(\begin{array}{ll}\mathrm{Na}^+&\ \ \ \ \ \mathrm{\ NO}_3-\\
\mathrm{Sr}^{2+}&\mathrm{\ \ \ \ \ \ SO}_4^{2-}\\
\mathrm{Co}^{2+}&\mathrm{\ \ \ \ \ \ S}^{2-}\\
\mathrm{Pb}^{2+}&\mathrm{\ \ \ \ \ \ CO}_3^{2-}\end{array}\)

ANSWER:

 

Step 1 of 2

We can generally assume that salts dissociate into their ions when they dissolve in water. Ionic compounds dissolve in water if the energy given off when the ions interact with water molecules compensates for the energy needed to break the ionic bonds in the solid and the energy required to separate the water molecules so that the ions can be inserted into solution.

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