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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 7 - Problem 69p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 7 - Problem 69p

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# Correct any incorrect equations. If no reaction occurs, write NO REACTION.(a)

ISBN: 9780321910295 34

## Solution for problem 69P Chapter 7

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition

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Problem 69P

Correct any incorrect equations. If no reaction occurs, write NO REACTION.

(a) $$\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{BaSO}_{4}(s)+2 \mathrm{NH}_{4} \mathrm{NO}_{3}(a q)$$

(b) $$\mathrm{BaS}(a q)+2 \mathrm{KCl}(a q) \rightarrow \mathrm{BaCl}_{2}(s)+\mathrm{K}_{2} \mathrm{~S}(a q)$$

(c) $$2 \mathrm{KI}(a q)+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q) \rightarrow \mathrm{PbI}_{2}(s)+2 \mathrm{KNO}_{3}(a q)$$

(d) $$\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{LiCl}(a q) \rightarrow 2 \mathrm{LiNO}_{3}(s)+\mathrm{PbCl}_{2}(a q)$$

Equation Transcription:

Text Transcription:

Ba(NO_3)_2 (aq) + (NH_4)_2 SO_4 (aq) right arrow BaSO_4 (s) + 2 NH_4 NO_3 (aq)

BaS(aq) + 2 KCl (aq) right arrow BaCl_2 (s) + K_2 S(aq)

2 KI(aq) + Pb(NO_3)_2 (aq) right arrow PbI_2(s) + 2 KNO_3 (aq)

Pb(NO_3)_2 (aq) + 2 LiCl(aq) right arrow 2 LiNO_3 (s) + PbCl_2 (aq)

Step-by-Step Solution:
Step 1 of 3

Solution 69P

Here, we have to correct any incorrect equations and if no reaction occurs, write NO REACTION.

(a) Ba(NO3)2(aq) + (NH4)2SO4(aq) → BaSO4(s) + 2 NH4NO3(aq) :

The above equation is correct. The products formed - BaSO4 is insoluble in water and hence the precipitation equation is correct.

(b) BaS(aq) + 2 KCl(aq) → BaCl2(s) + K2S(aq):

The product formed here, BaCl2(Barium chloride) is soluble in water and K2S(Potassium Sulfide) is also soluble. As both the products formed here is soluble in water, the precipitate is not formed and there will be NO REACTION.

(c) 2 KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq) :

The product formed here, PbI2(Lead(II) iodide) is insoluble in water and KNO3(Potassium nitrate) is soluble in water. Hence, the above precipitation reaction is correct.

(d) Pb(NO3)2(aq) + 2 LiCl(aq) → 2 LiNO3(s) + PbCl2(aq) :

The product formed here, LiNO3(Lithium nitrate) is soluble in water and PbCl2(Lead(II) chloride) is insoluble in water. Hence, the above equation is incorrect.

Hence the correct equation is :

Pb(NO3)2(aq) + 2 LiCl(aq) → 2 LiNO3(aq) + PbCl2(s)

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

This full solution covers the following key subjects: reaction, kno, BAS, baso, correct. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 69P from chapter: 7 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 69P from 7 chapter was answered, more than 2645 students have viewed the full step-by-step answer. The answer to “?Correct any incorrect equations. If no reaction occurs, write NO REACTION.(a) $$\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{BaSO}_{4}(s)+2 \mathrm{NH}_{4} \mathrm{NO}_{3}(a q)$$(b) $$\mathrm{BaS}(a q)+2 \mathrm{KCl}(a q) \rightarrow \mathrm{BaCl}_{2}(s)+\mathrm{K}_{2} \mathrm{~S}(a q)$$(c) $$2 \mathrm{KI}(a q)+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q) \rightarrow \mathrm{PbI}_{2}(s)+2 \mathrm{KNO}_{3}(a q)$$(d) $$\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{LiCl}(a q) \rightarrow 2 \mathrm{LiNO}_{3}(s)+\mathrm{PbCl}_{2}(a q)$$Equation Transcription:Text Transcription:Ba(NO_3)_2 (aq) + (NH_4)_2 SO_4 (aq) right arrow BaSO_4 (s) + 2 NH_4 NO_3 (aq)BaS(aq) + 2 KCl (aq) right arrow BaCl_2 (s) + K_2 S(aq)2 KI(aq) + Pb(NO_3)_2 (aq) right arrow PbI_2(s) + 2 KNO_3 (aq)Pb(NO_3)_2 (aq) + 2 LiCl(aq) right arrow 2 LiNO_3 (s) + PbCl_2 (aq)” is broken down into a number of easy to follow steps, and 94 words. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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