Lead ions can be removed from solution by precipitation with sulfate ions. Suppose a solution contains lead(II) nitrate. Write a complete ionic and net ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.
Here, we are going to write a complete ionic and net ionic equation for the given reaction.
Net ionic equation shows only those chemical species which are taking part in a chemical reaction. while writing the ionic equation, we write out all the soluble compounds as ions and eliminate ions common to both the reactants and products. This will give us the net ionic equation.
The balanced molecular equation for the given reaction is:
Pb(NO3)2(aq) + K2SO4(aq) → PbSO4(s) + 2KNO3(aq)
Converting the soluble compounds into ions, we get the complete ionic equation.Thus, the complete ionic equation for the above reaction is:
Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + SO42-(aq) → PbSO4(s) + 2K+(aq) + 2NO3-(aq)