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Get answer: Predict the products of each reaction and write balanced complete ionic and

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 98P Chapter 7

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 98P

PROBLEM 98P

Predict the products of each reaction and write balanced complete ionic and net ionic equations for each. If no reaction occurs, write NO REACTION.

(a) H2SO4(aq) + HNO3(aq) →

(b) NaOH(aq) + LiOH(aq) →

(c) Cr(NO3)3(aq) + LiOH(aq) →

(d) HCl(aq) + Hg2(NO3)2(aq) →

Step-by-Step Solution:
Step 1 of 3

Solution 98P

(a) H2SO4(aq) + HNO3(aq) →No reaction

(b) NaOH(aq) + LiOH(aq) →No reaction

(c) Cr(NO3)3(aq) + LiOH(aq) →Cr(OH)3(s)+Li(NO3)3(aq)  are the products of the reaction

Balanced ionic equation will be

Cr3+ (aq)+ 3NO3-(aq) + 3Li+(aq) +3OH- (aq) ---> Cr(OH)3(s) + 3NO3-(aq) + 3Li+ (aq)

cancelling spectator ions, NO3-(aq) and K+ ,on both sides we get net ionic equation which is:

Cr3+(aq)+ 3OH-(aq) ---> Cr(OH)3(s)

(d)HCl(aq) + Hg2(NO3)2(aq) →Hg2Cl2(s)+2HNO3(aq)are the products of the reaction

Balanced ionic equation will be

2H+ (aq) + 2Cl-(aq) +2 Hg2+ (aq)+ 2NO3-(aq) ---> Hg2Cl2(s)+2NO3-(aq) + 2H+(aq)

Upon removing spectator ions ,NO3-and H+ , we get net ionic equation which is:

2Cl-(aq) + 2Hg2+(aq) ---> Hg2Cl2(s)

Step 2 of 3

Chapter 7, Problem 98P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Get answer: Predict the products of each reaction and write balanced complete ionic and