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Classify each reaction in as many ways as possible.(a) 2

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 101P Chapter 7

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 0 329 Reviews
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5
Problem 101P

PROBLEM 101P

Classify each reaction in as many ways as possible.

(a) 2 Al(s) + 3 Cu(NO3)2(aq) → 2 Al(NO3)3(aq) + 3 Cu(s)

(b) HBr(aq) + KHSO3(aq) → H2O(l) + SO2(g) + NaBr(aq)

(c) 2 HI(aq) + Na2S(aq) → H2S(g) + 2 NaI(aq)

(d) K2CO3(aq) + FeBr2(aq) → FeCO3(s) + 2 KBr(aq)

Step-by-Step Solution:
Step 1 of 3

Solution 101P

(a) 2Al(s) + 3Cu(NO3)2(aq) → 2 Al(NO3)3(aq) + 3Cu(s)

1. single displacement: the single element (Al) is displacing the Cu2+ ion in the compound.

(b) HBr(aq) + KHSO3(aq) → H2O(l) + SO2(g) + NaBr(aq)

2. acid-base/gas-evolution: the strong acid reacts with the basic salt to form KBr and H2SO3. However, H2SO3 is not stable in solution and produces water and SO2 gas. FYI: An acid-base reaction is a special type of double displacement reaction,...

Step 2 of 3

Chapter 7, Problem 101P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: classify, febr, feco, hbr, kbr. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Since the solution to 101P from 7 chapter was answered, more than 2211 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 101P from chapter: 7 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Classify each reaction in as many ways as possible.(a) 2 Al(s) + 3 Cu(NO3)2(aq) ? 2 Al(NO3)3(aq) + 3 Cu(s)(b) HBr(aq) + KHSO3(aq) ? H2O(l) + SO2(g) + NaBr(aq)(c) 2 HI(aq) + Na2S(aq) ? H2S(g) + 2 NaI(aq)(d) K2CO3(aq) + FeBr2(aq) ? FeCO3(s) + 2 KBr(aq)” is broken down into a number of easy to follow steps, and 46 words.

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