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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 108P Chapter 7

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 108P

PROBLEM 108P

A solution contains one or more of the following ions: Hg22+, Ba2+, and Fe2+. When potassium chloride is added to the solution, a precipitate forms. The precipitate is filtered off and potassium sulfate is added to the remaining solution, producing no precipitate. When potassium carbonate is added to the remaining solution, a precipitate occurs. Which ions were present in the original solution? Write net ionic equations for the formation of each of the precipitates observed.

Step-by-Step Solution:
Step 1 of 3

Solution 108P

The addition of KCl with Hg22+ will form a precipitate of Hg2Cl2 ,

This leaves you with Ba2+ and Fe2+ ions.

The Ba2+ ion should precipitate with the sulfate. Since it doesn't, there is no net ionic equation.

Thus the last ion is  Fe2+ which form a precipitate with carbonate ion.

So the first net ionic equation:

Hg2 2+ (aq) + 2Cl- (aq)...

Step 2 of 3

Chapter 7, Problem 108P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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