For the reaction shown, calculate how many moles of NH3 form when each amount of reactant completely reacts.
3 N2H4(l) → 4 NH3(g) + N2(g)
(a) 5.3 mol N2H4
(b) 2.28 mol N2H4
(c) 5.8 × 10−2 mol N2H4
(d) 9.76 × 107 mol N2H4
Here, we are going to calculate the number of moles of NH3 formed when the given amounts of N2H4 completely reacts.
The given chemical reaction is:
3N2H4(l) → 4NH3(g) + N2(g)
From the above equation, it is clear that, 3 moles of N2H4 reacts completely to give 4 moles of NH3 as product.
Therefore, 1 mole of N2H4 will give (4/3 = 1.33) mol of NH3 on complete reaction.