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For the reaction shown, calculate how many moles of NH3

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Problem 18P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 18P

 PROBLEM 18P

For the reaction shown, calculate how many moles of NH3 form when each amount of reactant completely reacts.

3 N2H4(l) → 4 NH3(g) + N2(g)

(a) 5.3 mol N2H4

(b) 2.28 mol N2H4

(c) 5.8 × 10−2 mol N2H4

(d) 9.76 × 107 mol N2H4

Step-by-Step Solution:

Solution 18P

Here, we are going to calculate the number of moles of NH3 formed when the given amounts of N2H4 completely reacts.

Step 1:

The given chemical reaction is:

                                3N2H4(l) → 4NH3(g) + N2(g)

From the above equation, it is clear that, 3 moles of N2H4 reacts completely to give 4 moles of NH3 as product.

Therefore, 1 mole of N2H4 will give (4/3 = 1.33) mol of NH3 on complete reaction.

Step 2 of 2

Chapter 8, Problem 18P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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