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Consider the unbalanced equation for the neutralization of acetic acid:HC2H3O2(aq) +

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 28P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 28P

PROBLEM 28P

Consider the unbalanced equation for the neutralization of acetic acid:

HC2H3O2(aq) + Ca(OH)2(aq) → H2O(l) + Ca(C2H3O2)2(aq)

Balance the equation and determine how many moles of Ca(OH)2 are required to completely neutralize 1.07 mol of HC2H3O2.

Step-by-Step Solution:
Step 1 of 3

Solution 28P

The correct balanced equation is:

2HC2H3O2(aq) + Ca(OH)2(aq)  2H2O(l) + Ca(C2H3O2)2 

Here we have to calculate the amount of  Ca(OH)2 are required to completely neutralize 1.07 mol of HC2H3O2.

2 mol HC2H3O2 react with 1 mol Ca(OH)2 

2.10 mol HC2H3O2  (1 mol Ca(OH)2 / 2 mol HC2H3O2) = 1.05 mol Ca(OH)2

Thus 1.05 mol of Ca(OH)2 required to neutralize  1.07 mol of HC2H3O2.

Step 2 of 3

Chapter 8, Problem 28P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Consider the unbalanced equation for the neutralization of acetic acid:HC2H3O2(aq) +