Solution Found!
Consider the unbalanced equation for the neutralization of acetic acid:HC2H3O2(aq) +
Chapter 8, Problem 28P(choose chapter or problem)
Consider the unbalanced equation for the neutralization of acetic acid:
\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)
Balance the equation and determine how many moles of \(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).
Questions & Answers
QUESTION:
Consider the unbalanced equation for the neutralization of acetic acid:
\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)
Balance the equation and determine how many moles of \(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).
ANSWER:Step 1 of 2
The given unbalanced equation is
\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)
The balanced equation:
\(2 \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(\mathrm{aq})+\mathrm{Ca}\left(\mathrm{OH}_{2}\right)(\mathrm{aq}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(\mathrm{aq})\)
We have to determine how many moles of
\(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of
\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).