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Consider the unbalanced equation for the neutralization of acetic acid:HC2H3O2(aq) +

Chapter 8, Problem 28P

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QUESTION:

Consider the unbalanced equation for the neutralization of acetic acid:

\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)

Balance the equation and determine how many moles of \(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).

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QUESTION:

Consider the unbalanced equation for the neutralization of acetic acid:

\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)

Balance the equation and determine how many moles of \(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).

ANSWER:

Step 1 of 2

The given unbalanced equation is

\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)

The balanced equation:

\(2 \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(\mathrm{aq})+\mathrm{Ca}\left(\mathrm{OH}_{2}\right)(\mathrm{aq}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(\mathrm{aq})\)

We have to determine how many moles of 

\(\mathrm{Ca}(\mathrm{OH})_{2}\) are required to completely neutralize 1.07 mol of 

\(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\).

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