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For each acid-base reaction, calculate how many grams of

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 39P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 39P

PROBLEM 39P

For each acid-base reaction, calculate how many grams of acid are necessary to completely react with and neutralize 2.5 g of the base.

(a) HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)

(b) 2 HNO3(aq) + Ca(OH)2(aq) → 2 H2O(l ) + Ca(NO3)2 (aq)

(c) H2SO4(aq) + 2 KOH(aq) → 2 H2O(l) + K2SO4(aq)

Step-by-Step Solution:
Step 1 of 3

Solution 39P

(a) HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)

According to the equation 1 mole of NaOH reacts with 1 mole of HCl to give 1 mole NaCl and water

Molecular weight of NaOH=40

Molecular weight of HCL=36.5

This means that 40 g NaOH needs 36.5 grams of HCl

Thus amount of acid  required for reaction of 2.5 grams of NaOH =36.5/40

2.5=2.281grams

(b) 2 HNO3(aq) + Ca(OH)2(aq) → 2 H2O(l ) + Ca(NO3)2 (aq)

According to the equation 2 mole of HNO3 reacts with 1 mole of Ca(OH)2 to give 1 mole  Ca(NO3)2and 2 moles of water

Molecular weight of HNO3=63

Molecular weight of Ca(OH)2=74

This...

Step 2 of 3

Chapter 8, Problem 39P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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