Determine the theoretical yield of C when each of the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Problem 46P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo Tro

Introductory Chemistry | 5th Edition

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Problem 46P

PROBLEM 46P

Determine the theoretical yield of C when each of the initial quantities of A and B is allowed to react in the generic reaction:

2 A + 3 B → 2 C

(a) 2 mol A; 4 mol B

(b) 3 mol A; 3 mol B

(c) 5 mol A; 6 mol B

(d) 4 mol A; 5 mol B

Step-by-Step Solution:

Solution 46P

Step 1:

(a)2 mol A; 4 mol B

For these you need to set up proportions to find the theoretical yield. The general reaction

2A + 3B  2C

Means that 2 moles of A and 3 moles of B react to make 2 moles of C. The proportion you need to set up is this:

moles of reactant in general reaction =    moles of reactant in problem    

moles of product in general reaction   =   moles of product being asked for

So we have for problem A:

2 mol A = 2 mol A

2 mol C  =    x

x = 2 mol C

and:

3 mol B = 4 mol B

2 mol C        x

x = 8/3 mol C (2.667 mol)

As you can see, I set up proportions for both Reactant A and Reactant B as given in the problem. The theoretical yield is the proportion which gives the least amount of moles of product, which in this case is the 2 moles of Reactant A, which gave 2 moles of Product C, whereas the 4 moles of Reactant B would have given 2.667 moles of C (thus, A is called the limiting reactant, since, in the reaction given by problem A, all of Reactant A would have reacted with most of B to yield 2 moles of C). So the theoretical yield is 2 moles of C.

Step 2:

(b) 3 mol A; 3 mol B

Here,

2 mol A = 3 mol A

2 mol C       x

x = 3 mol C

and:

3 mol B = 4 mol B

2 mol C        x

x = 8/3 = 2.6 mol C

Here the theoretical yield is 2.6 moles

Step 3 of 4

Chapter 8, Problem 46P is Solved
Step 4 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo Tro
ISBN: 9780321910295

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