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Solved: For the reaction shown, find the limiting reactant for each of the initial

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 48P Chapter 8

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 48P

PROBLEM 48P

For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4 Cr(s) + 3 O2(g) → 2 Cr2O3(s)

(a) 1 mol Cr; 1 mol O2

(b) 4 mol Cr; 2.5 mol O2

(c) 12 mol Cr; 10 mol O2

(d) 14.8 mol Cr; 10.3 mol O2

Step-by-Step Solution:

Problem 48P

For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

(a) 1 mol Cr; 1 mol O2

(b) 4 mol Cr; 2.5 mol O2

(c) 12 mol Cr; 10 mol O2

(d) 14.8 mol Cr; 10.3 mol O2

                                                          Step by step solution

Step 1 of 4

a)

The limiting reactant in a reaction is the reactant that produces the least amount of product.

The given chemical reaction is as follows.

                                     

From the balanced chemical reaction, four moles of chromium reacts with three moles of oxygen molecules to produce two moles of chromium oxide.

Let’s calculate the number of moles of product that can be produced from one mol of “Cr” and one mol of oxygen.

                                   

                                   

Hence, “Cr” produces less amount of chromium oxide.

Therefore, the limiting reactant is 1 mol Cr.

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Step 2 of 4

Chapter 8, Problem 48P is Solved
Step 3 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: For the reaction shown, find the limiting reactant for each of the initial