For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.
4 Cr(s) + 3 O2(g) → 2 Cr2O3(s)
(a) 1 mol Cr; 1 mol O2
(b) 4 mol Cr; 2.5 mol O2
(c) 12 mol Cr; 10 mol O2
(d) 14.8 mol Cr; 10.3 mol O2
The theoretical yield is the proportion which gives the least amount of moles of product, and is called as limiting reactant,
You have 4 Cr to 3 O2. That means you need more Cr than O2.
a] 1 mol Cr has to be bigger than 1 mol O2. Since it is not, Cr is the limiting reagent.
b] 4 mol of Cr 2.5 mol of O2
If you have 4 mol of Cr you need 3 mol of O2, the limiting reagent is O2
c] 12 mol of Cr is 3 times as large as 4. Therefore you have to multiply the 3 in front of O2 by 3. when you do you get 9 moles of O2. Since there...