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The mass of a sugar crystal with 1.8 × 10¹? sucrose molecules
Chapter 8, Problem 49P(choose chapter or problem)
For the reaction shown, calculate the theoretical yield of product in moles for each of the initial quantities of reactants.
\(2 \mathrm{Mn}(\mathrm{s})+3 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{MnO}_{3}(\mathrm{~s})\)
(a) 2 mol Mn; 2 mol \(\mathrm{O}_{2}\)
(b) 4.8 mol Mn; 8.5 mol \(\mathrm{O}_{2}\)
(c) 0.114 mol Mn; 0.161 mol \(\mathrm{O}_{2}\)
(d) 27.5 mol Mn; 43.8 mol \(\mathrm{O}_{2}\)
Questions & Answers
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QUESTION:
For the reaction shown, calculate the theoretical yield of product in moles for each of the initial quantities of reactants.
\(2 \mathrm{Mn}(\mathrm{s})+3 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{MnO}_{3}(\mathrm{~s})\)
(a) 2 mol Mn; 2 mol \(\mathrm{O}_{2}\)
(b) 4.8 mol Mn; 8.5 mol \(\mathrm{O}_{2}\)
(c) 0.114 mol Mn; 0.161 mol \(\mathrm{O}_{2}\)
(d) 27.5 mol Mn; 43.8 mol \(\mathrm{O}_{2}\)
ANSWER:
Step 1 of 5
We have given the chemical reaction
\(2 \mathrm{Mn}(s)+3 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{MnO}_{3}(s)\)
Watch The Answer!
The mass of a sugar crystal with 1.8 × 10¹? sucrose molecules
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This video guides you through calculating the theoretical yield of a product in moles for a given chemical reaction by identifying the limiting reactant. It explains how to determine the limiting reactant for different quantities of reactants and then calculates the corresponding moles of the product, ensuring an accurate theoretical yield estimation.
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