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For the reaction shown, calculate the theoretical yield of the product in grains for
Chapter 8, Problem 57P(choose chapter or problem)
For the reaction shown, calculate the theoretical yield of the product in grains for each of the initial quantities of reactants.
\(2 \ \mathrm{Al}(s)+3 \ \mathrm{Cl}_{2}(g) \longrightarrow 2 \ \mathrm{AlCl}_{3}(s)\)
(a) \(1.0 \mathrm{~g} \ \mathrm{Al} ; 1.0 \mathrm{~g} \ \mathrm{Cl}_{2}\)
(b) \(5.5 \mathrm{~g} \ \mathrm{Al} ; 19.8 \mathrm{~g} \ \mathrm{Cl}_{2}\)
(c) \(0.439 \mathrm{~g} \ \mathrm{Al} ; 2.29 \mathrm{~g} \ \mathrm{Cl}_{2}\)
Questions & Answers
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QUESTION:
For the reaction shown, calculate the theoretical yield of the product in grains for each of the initial quantities of reactants.
\(2 \ \mathrm{Al}(s)+3 \ \mathrm{Cl}_{2}(g) \longrightarrow 2 \ \mathrm{AlCl}_{3}(s)\)
(a) \(1.0 \mathrm{~g} \ \mathrm{Al} ; 1.0 \mathrm{~g} \ \mathrm{Cl}_{2}\)
(b) \(5.5 \mathrm{~g} \ \mathrm{Al} ; 19.8 \mathrm{~g} \ \mathrm{Cl}_{2}\)
(c) \(0.439 \mathrm{~g} \ \mathrm{Al} ; 2.29 \mathrm{~g} \ \mathrm{Cl}_{2}\)
ANSWER:Step 1 of 4
Limiting reactant is the reactant that is completely consumed in a chemical reaction.
Theoretical yield-the amount of product that can be made in a chemical reaction based on the amount of limiting reactant.
Chemical reaction
\(2 \mathrm{Al}(\mathrm{s})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{AlCl}_{3}(\mathrm{~s})\)
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